Answer:
there is no real number solution
Step-by-step explanation:
Given
x² + 6x = - 10
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(3)x + 9 = - 10 + 9
(x + 3)² = - 1 ( take the square root of both sides )
x + 3 = ± [tex]\sqrt{-1}[/tex]
there is no real number whose square is - 1
