Answer:
2π3,(4π3)
Step-by-step explanation:
Answer:sin(inverse)(3/2)
sin(2x)-3cosx=0 sin2x=2sinxcosx
2sinxcosx-3cosx=0
2sinxcosx=3cosx
Divide both sides by cosx
2sinxcosx ➗ cosx =3cosx ➗ cosx
2sinx=3
Divide both sides by 2
2sinx ➗ 2=3 ➗ 2
sinx=3/2
x=sin(inverse)(3/2)
