Answer:
[tex]\frac{5\pm\sqrt{73}}{4}[/tex]
Step-by-step explanation:
The quadratic formula:
[tex]\frac{-b+\sqrt{b^2-4ac}}{2a}[/tex]
So, we need to move all the terms to one side of the equation, which now becomes
[tex]2x^2-5x-6=0[/tex]
Plugging in the numbers and you'll get the two roots/
