Answer:
1
Step-by-step explanation:
r(t) = (cos t, t³)
Take first derivative to find velocity:
v(t) = dr/dt
v(t) = (-sin t, 3t²)
Take derivative again to find acceleration:
a(t) = dv/dt
a(t) = (-cos t, 6t)
At t=0, the acceleration's magnitude is:
a(0) = (-1, 0)
|a(0)| = √((-1)² + 0²)
|a(0)| = 1
