Answer:
A.
Step-by-step explanation:
Firstly, [tex]x^{-y} = \frac{1}{x^y}[/tex], so in this case, you multiply [tex](6^{-8})^4[/tex], which equals [tex]6^{-32}[/tex]. Then, plug it into [tex]x^{-y} = \frac{1}{x^y}[/tex] and you get
[tex]6^{-32} = \frac{1}{6^{32}}[/tex], so it's [tex]\boxed{A.}[/tex]
