Answer:
4.38 Grams of C
Explanation:
How many grams of C are required to react with 52.6grams of Fe2O2?
Fe2O2 + C = 2Fe + CO2
Ratio 1:1
Fe2O2 = 144 Molar Mass
Fe2O2 52.6/144 = 0.365Moles of Fe2O2
Fe =56grams/mole = Charge 2+, 3+
O = 16grams/mole = Charge 2-
C = 12grams/mole = Charge 4+
So Ratio is 1:1 so we only need 0.365Moles of C so 4.38grams
