Answer: 1.8
Step-by-step explanation:
[tex]\dfrac{2}{3}x-\dfrac{1}{5}>1\\\\\dfrac{2}{3}x\quad \quad >1+\dfrac{1}{5}\\\\\\\dfrac{2}{3}x\quad \quad >\dfrac{6}{5}\\\\\\\dfrac{2}{3}x\bigg(\dfrac{3}{2}\bigg) \ >\dfrac{6}{5}\bigg(\dfrac{3}{2}\bigg) \\\\\\x\qquad \quad >\dfrac{18}{10}\\\\\\x\qquad \quad >1.8[/tex]
