Respuesta :

mhanifa

Answer:

minimum -45, maximum 32

Step-by-step explanation:

C=4x-3y

x≥0, y≥4, x+y≤15

Maximum value of C can be achieved at max x and min y

  • min y=4 => max x=15-4=11
  • C=4*11-3*4= 32

Minimum value of C can be achieved at min x and max y

  • min x=0, max y =15
  • C=4*0-3*15= -45

So answer is minimum -45, maximum 32

Otras preguntas