Answer:
You can denote the width of the rectangle as x,
than the length of the rectangle will be 2x
and the perimeter of the rectangle will be two length plus two width and it should be equal to 54 in
and the equation will look 2(2x)+2x=54
solving the equation 6x=54, x=9in
So the width of the rectangle is 9in and the length is 9*2=18in
and the area of the rectangle is 9*18=162 sq in.
