Answer:
[tex]q=\frac{1}{6}p- \frac{1}{2}r[/tex]
Step-by-step explanation:
[tex]p=3(2q+r)[/tex]
[tex]2q+r=\frac{p}{3}[/tex]
[tex]2q=\frac{p}{3} -r[/tex]
[tex]q=\frac{p}{6}- \frac{r}{2}[/tex]
