Answer:
Step-by-step explanation:
[tex]2y^2 = x + 4 \rightarrow x = 2y^2 -4[/tex]
[tex]x=y^2[/tex]
intersection points
[tex]2y^2 - 4 = y^2[/tex]
[tex]y^2 =4[/tex]
[tex]y = \pm 2 \rightarrow (4, -2)~ and~ (4, 2)[/tex]
[tex]\int\limits^2_{-2} (y^2-(2y^2-4)} \, dy[/tex]
You finish it by yourself
