Answer:
58°C
Step-by-step explanation:
Heat absorbed by hot water + heat absorbed by cold water = 0
m₁C₁ΔT₁ + m₂C₂ΔT₂ = 0
(300 g) (4.184 J/g/K) (T − 90°C) + (200 g) (4.184 J/g/K) (T − 10°C) = 0
(300 g) (T − 90°C) + (200 g) (T − 10°C) = 0
(300 g) (T − 90°C) = -(200 g) (T − 10°C)
3 (T − 90°C) = -2 (T − 10°C)
3T − 270°C = -2T + 20°C
5T = 290°C
T = 58°C
