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Maya is signing her daughter up for summer activities. Some of the activities cost $10, and some of them cost $20. Maya pays a total of $130 for 9 activities. How many of each activity did she sign her daughter up for?

Respuesta :

bellasophiasmom

Answer:

(5,4)

Step-by-step explanation:

10x + 20y = 130

x + y = 9

you can solve by substitution

x = 9 - y

10 (9 - y) + 20y = 130

90 - 10y + 20y = 130

90 + 10y = 130 (subtract 90 from both sides)

10y = 40

y = 4

Plug the answer back in the original equations to solve for x

x + 4 = 9 (subtract 4 from both sides)

x = 5

The number of activities that cost $10 is 4.

The number of activities that cost $20 is 5.

What are the linear equations that represent the question?

10a + 20b = 130 equation 1

a + b = 9 equation 2

Where:

  • a = number of activities that cost $10
  • b = number of activities that cost $20

What is the number of activities cost $20?

Multiply equation 2 by 10

10a + 10b = 90 equation 3

Subtract equation 3 from equation 2

$10b = $40

b = $40 / $10

b = 4

What is the number of activities cost $10?

Subtract 4 from 9: 9 - 4 = 5

To learn more about simultaneous equations, please check: https://brainly.com/question/25875552

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