Answer:
[tex]\textbf{J. }\dfrac{1}{x^2-x}[/tex]
Step-by-step explanation:
Factor the denominator and cancel the common factor.
[tex]\dfrac{x+1}{x^3-x}=\dfrac{x+1}{x(x^2-1)}=\dfrac{x+1}{x(x-1)(x+1)}=\dfrac{1}{x(x-1)}\\\\=\boxed{\dfrac{1}{x^2-x}}[/tex]
