Find the equation of the line that is the perpendicular bisector of AB
A. y=2/3x+2
B. y=-3/2x+2.5
C. Y=-2/3x+13/6
D. Y=-2/3x+13/6

Find the equation of the line that is the perpendicular bisector of AB A y23x2 B y32x25 C Y23x136 D Y23x136 class=

Respuesta :

Answer:

D. y= -2/3x + 13/6

solve:

y-3/2= -2/3 (x-1)

y= -2/3x + 2/3 + 3\2

y = -2\3x + 4+9/6

y= -2/3 x + 13/6