Answer:
B
Step-by-step explanation:
[tex] \sqrt{19} + \frac{7}{2} \: is \: irrational \: \\ \because \: \sqrt{19} \: is \: irrational \: and \: \frac{7}{2} is \: rational \\ adding \: any \: rational \: number \: in \: irrational \: number \\ results \: in \: irrational \: number.[/tex]
