Answer:
Explanation:
2 H₂(g) + O₂(g) → 2 H₂O(g
2 moles 1 mole 2 mole
50 g of H₂ = 50 /2 = 25 moles of H₂
100 g of O₂ = 100 / 32 = 3.125 moles of O₂
So oxygen is the limiting reagent .
3.125 moles of O₂ will react with 6.25 moles of H₂ to give 6.25 moles of H₂O .
Hence moles of H₂O produced = 6.25 moles .
