Answer:
1.400 mol
Explanation:
To convert grams to moles, you will need the molar mass. The molar mass of iron(iii) sulfate is 399.88 g/mol. Divide grams by the molar mass to find moles.
(560.0 g)/(399.88 g/mol) = 1.400 mol
There are 1.400 mol present in 560.0 g of iron(iii) sulfate.
