Answer:
D. [tex] 8 {m}^{ - 1} n[/tex]
Step-by-step explanation:
[tex] \huge \frac{(4 {m}^{2} n)^{2} }{2 {m}^{5}n } \\ \\ \huge= \frac{16 {m}^{4} {n}^{2} }{2 {m}^{5}n } \\ \\ \huge = 8 {m}^{4 - 5} {n}^{2 - 1} \\ \\ \huge \purple{ \boxed{= 8 {m}^{ - 1} n}}[/tex]
