Answer:
[tex]\huge\boxed{(f-g)(2)=17}[/tex]
Step-by-step explanation:
[tex](f-g)(x)=f(x)-g(x)\\\\f(x)=2x^2+8;\ g(x)=x-3\\\\(f-g)(2)=f(2)-g(2)\\\\f(2)\ [g(2)]-\text{substitute}\ x=2\ \text{to}\ f(x)\ [g(x)]\\\\f(2)=2(2^2)+8=2(4)+8=8+8=16\\g(2)=2-3=-1\\\\(f-g)(2)=16-(-1)=16+1=17[/tex]
