Answer:
[tex]-6 \le p < 0[/tex]
In interval notation, the solution is [-6, 0).
Step-by-step explanation:
[tex]-3 \le \dfrac{p}{2} < 0[/tex]
Multiply the three sides by 2.
[tex]-3 \times 2 \le \dfrac{p}{2} \times 2 < 0 \times 2[/tex]
[tex]-6 \le p < 0[/tex]
In interval notation, the solution is [-6, 0).
