Answer:
2(3x +2)(x +4)
Step-by-step explanation:
[tex]6x^2+28x+16\\\\\mathrm{Factor\:out\:common\:term\:}2:\quad 2\left(3x^2+14x+8\right)\\\\=2\left(3x^2+14x+8\right)\\\\\mathrm{Factor}\:3x^2+14x+8:\quad \left(3x+2\right)\left(x+4\right)\\\\=2\left(3x+2\right)\left(x+4\right)[/tex]
