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15-09-2016
Chemistry

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Calculate the amount of heat required to heat a 1.5 kg gold bar from 21°C to 68°C

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16-09-2016

[tex]Q=mc\Delta T\\\\ m=1,5kg=1500g\\ c_{Au}=0,129\frac{J}{g^{o}C}\\ \Delta T=68-21=47^{o}C\\\\ Q=1500g*0,129\frac{J}{g^{o}C}*47^{o}C=9094,5J[/tex]

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