Answer:
The given linear equation are
⇒9x+3y+12=0....eq1
⇒a1
=9,b1
=3,c1
=12
⇒18x+6y+24...eq2
⇒a2
=18,b2
=6,c2
=24
⇒a1/a2
=9/18 =1/2
⇒ b1/b2= 3/6 = 1/2
⇒ c1/c2= 12/24= 1/2
comparing
⇒ a1/a2,b1/b2,c1/c2
⇒ a1/a2=b1/b2=c1/c2
Hence, the line represented by eq1 and eq2 are coincidents
Step-by-step explanation:
