Answer:
d=117.33 m
Step-by-step explanation:
Initial velocity of planes, u = 0 (because they are at rest)
Acceleration, a = 3.3 m/s²
Final take off speed, v = 88 m/s
We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :
[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}[/tex]
Putting all the values, we get :
[tex]d=\dfrac{88^2-0^2}{2\times 33}\\\\d=117.34\ m[/tex]
Hence, the minimum allowed length for the runway is 117.33 m.
