Newhopeclub Newhopeclub

14-10-2020
Mathematics

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CAN YOU PLEASEEE HELP ME IM DESPERATE AND NEED THE ANSWER ASAP

CAN YOU PLEASEEE HELP ME IM DESPERATE AND NEED THE ANSWER ASAP class=

Respuesta :

marlynn2002 marlynn2002

14-10-2020

Answer:

6(x-3)(X^2+4)(x+1)=0

real answers:

(x-3)=0

x=3

x+1=0

x=-1

This numbers are not real:

x^2+4=0

x^2=-4

[tex]\sqrt{x}[/tex]= ±[tex]\sqrt{2}[/tex]

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