Answer:
14.25 m/s
Explanation:
In this problem, we need to find the horizontal component of a ball thrown at a 27 degree angle at 16 m/s.
It can be given by :
[tex]v_x=v\cos\theta\\\\=16\times \cos(27)\\\\=14.25\ m/s[/tex]
So, the horizontal component of the ball is 14.25 m/s.
