Answer:
[tex]-\frac{3}{2} <x<1[/tex]
Step-by-step explanation:
[tex]2x^{2} +3x-2x-3<0[/tex]
[tex]x(2x+3)-(2x+3)<0\\(2x+3)(x-1)<0\\When 2x+3=0 or x-1=0 \\x= -\frac{3}{2},1[/tex]
[tex]x<-\frac{3}{2} \\-\frac{3}{2} <x<1\\x<1[/tex]
