Answer:
13, 15, 17
Explanation:
Consider three consecutive odd integers (2n−1),(2n+1),(2n+3)
Where n is Integer?
If the sum of these odd integers is 45,
Then: (2n−1)+(2n+1)+(2n+3)=45
6n+3=45
6n=42
n=7
Substituting n=7 into (2n−1),(2n+1),(2n+3)
Gives 13, 15, 17
To check: 13+15+17=45
