Answer:
(A) 142.5 square inches
Step-by-step explanation:
It is given that A kite with two top triangles with height of 5 inches and a base 7.5 inches. The bottom two triangles share the base but have a height labeled 14 inches that is:
DE=5in, EC=7.5in, EB=14in
Now, area of the two top triangles of the kite=[tex]2(\frac{1}{2}{\times}EC{\times}DE)[/tex]
=[tex]EC{\times}DE[/tex]
=[tex]7.5{\times}5[/tex]
=[tex]37.5 square inches[/tex]
Also, area of the two bottom triangles of the given kite=[tex]2(\frac{1}{2}{\times}EC{\times}EB)[/tex]
=[tex]EC{\times}EB[/tex]
=[tex]7.5{\times}14[/tex]
=[tex]105 square inches[/tex]
Therefore, the total area of the kite=area of the two top triangles of the kite+area of the two bottom triangles of the given kite
=37.5+105
=142.5 square inches.
