loveskte1
loveskte1 loveskte1
  • 11-12-2020
  • Mathematics
contestada

Please help meeeee T~T

Please help meeeee TT class=

Respuesta :

kshah52 kshah52
  • 11-12-2020

Answer:  [tex]15x^{2} y^{3}[/tex]

Step-by-step explanation:

[tex]3x^2y*5y^2=(3*5)*x^2*y^{2+1} = 15x^{2} y^{3}[/tex]

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