Answer:
Step-by-step explanation:
1S. JM bisects ∠ KJL and ∠JMK ≅ ∠JML
1R. Given
2S. ∠KJM ≅ ∠LJM
2R. Angle bisectors form ≅ ∠s
3S. JM≅JM
3R. Reflexive Propriety ( segment is ≅ with itself)
4S. ΔJMK ≅ΔJML
4R. ASA theorem of congruency
5S. JK≅JL
5R. Coresponding parts of congruent Δs are congruent (CPCTC)
