Respuesta :

sashimjoshi8

Answer:

[H+]=10−4.18⋅mol⋅L−1

Explanation:

By definition, pH=−log10[H+]; equivalently, pH=−log10[H3O+].

We take antilogs..........

[H3O+]=10−4.18⋅mol⋅L−1=6.61×10−5⋅mol⋅L−1.

apologize if it is hard to read

Otras preguntas