Answer:
b
Step-by-step explanation:
Using the trigonometric identity
secx = [tex]\frac{1}{cosx}[/tex] and cos60° = [tex]\frac{1}{2}[/tex]
Given
sec [ [tex]sin^{-1}[/tex] [tex]\frac{\sqrt{3} }{2}[/tex] ] ← evaluate bracket
= sec60°
= [tex]\frac{1}{cos60}[/tex]
= [tex]\frac{1}{\frac{1}{2} }[/tex]
= 2 → b
