Answer:
y = 0.5 at x = 4
Step-by-step explanation:
According to question,
y is inversely proportional to cube of x i.e.
[tex]y\propto \dfrac{1}{x^3}\\\\y=\dfrac{k}{x^3}[/tex]
or
[tex]k=yx^3[/tex]
Put x = 2 and y = 4 in above expression to find k.
[tex]k=4\times (2)^3\\\\=32[/tex]
Now put x = 4 to given equation to find y.
[tex]y=\dfrac{32}{4^3}[/tex]
y = 0.5 or 1/2
So, the value of y is 0.5 when x = 4.
