Answer:
x<±1 and x< -3
Step-by-step explanation:
Given the inequality x^2-1/3x+9<0, we are to find the values of x that satisfies the inequality
x^2-1/3x+9<0
x^2-1/3x+9 (3x+9)²<0* (3x+9)²
(x^2-1)(3x+9) < 0
x²-1 < 0 and 3x + 9 <0
x²-1 < 0
x²<1
x<±√1
x<±1
Also 3x + 9 <0
3x < -9
x < -9/3
x < -3
Hence the required values of x are x<±1 and x< -3
