Respuesta :

madethisfortwitch1

Answer:

y¹⁵-20y¹⁴

Step-by-step explanation:

I'm going to assume that your problem looks like this

[tex](y-20)(y^5)^3[/tex]

[tex](x^n)^y=x^{n*y}[/tex]

which means we have

[tex](y-20)*y^{15}\\\\y^{16}-20y^{15}=ya\\\\*y^{15}-20y^{14}=a[/tex]

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