Answer:
A) 1/(3x+1)
Step-by-step explanation:
(x+2)/(x³+2x²-9x-18)÷(3x+1)/(x²-9)
(x+2)/(x+2)(x+3)(x-3)÷(3x+1)/(x+3)(x-3)
since it’s dividing by a fraction, invert and multiply
(x+2)/(x+2)(x+3)(x-3) times (x+3)(x-3)/(3x+1)
The (x+2)’s cancel out.
The (x+3)’s cancel out.
The (x-3)’s cancel out.
You are left with 1/(3x+1)
