Answer:
20.16 × 10^(23) molecules
Explanation:
We know that At STP, 22.4 L of any substance = 6.02 × 10^(23) molecules
Thus;
75 L of F2 at STP will give;
(75 × 6.02 × 10^(23))/22.4 = 20.16 × 10^(23) molecules
Number of molecules in 75.0 liters of F2 at STP = 20.16 × 10^(23) molecules
