Given :
The local approximation to the function g at x = 1/2 is y = 4x+1.
To Find :
The value of g(1/2) + g'(1/2).
Solution :
It is given that at g( y ) = 3x + 1 , at x = 1/2.
Differentiating g( y ) w.r.t x ,we get :
g( y )' = 3
So, g( y ) + g( y' ) = 3/2 + 1 + 3
g( y ) + g( y' ) = 11/2
Hence, this is the required solution.
