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How many moles of lithium hydroxide would be required to produce 67.5 g of Li₂CO₃ in the following chemical reaction?
2 LiOH(s) + CO₂(g) → Li₂CO₃(s) + H₂O(l)

Respuesta :

emdinh96oreat3
Molar mass Li2CO3 = 73.89 g/mol
Mol Li2CO3 = 67.5/73.89 =0.91 mol
Mol LiOH = 1.82 mol
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