Answer:
2=k^1/x
3=k^1/y
12=k^1/z.......we get...
(atq)------k^1/x=k^1/y=k^1/z
(*a^m=b^m......b=a)
~1/x=1/y=1/z
1/z=1/y+1/x×2
(12=3+2×2)
1/z=1/y+2/x.....proved
