Answer:
Step-by-step explanation:
Substitute in the expression,
\sin^230^\circ-\cos^230^\circ=(\frac{1}{2})^2-(\frac{\sqrt3}{2})^2sin
2
30
∘
−cos
2
30
∘
=(
2
1
)
2
−(
2
3
)
2
\sin^230^\circ-\cos^230^\circ=\frac{1}{4}-\frac{3}{4}sin
2
30
∘
−cos
2
30
∘
=
4
1
−
4
3
\sin^230^\circ-\cos^230^\circ=-\frac{2}{4}sin
2
30
∘
−cos
2
30
∘
=−
4
2
\sin^230^\circ-\cos^230^\circ=-\frac{1}{2}sin
2
30
∘
−cos
2
30
∘
=−
2
1
