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12-03-2021
Chemistry

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A compound is found to have a composition of 35.880% Cr, 21.076% P, and 43,545% O
What is the empirical formula of the compound?

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Аноним Аноним

12-03-2021

Explanation:

Cr=35.880/51=0.73≈0.7

P=21.076/31=0.67≈0.7

O=43.543/16=2.71

Divide each by 0.7 u get

Cr=1 ,P =1, O=4

Empirical formula is CrPO4

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