Respuesta :

dreadteamleader
(-1,1) is the correct answer.

Answer:

we have

(y-y1)/(x-x1)=(y2-y1)/(x2-x1)

(y-1)/(x--2)=(-1-1)/(1--2)

(y-1)/(x+2)=(-2)/3

3(y-1)=(-2(x+2))

3y-3=-2x-4

2x+3y-3+4=0

2x+3y+1=0 is a required equation

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