Answer:
[tex]T_7 = \frac{64}{729}[/tex]
Step-by-step explanation:
Given
[tex]a =1[/tex]
[tex]r = \frac{2}{3}[/tex]
Required
Determine the 7th term
The nth term of a gp is:
[tex]T_n = a * r^{n-1[/tex]
So, we have:
[tex]T_7 = 1 * \frac{2}{3}^{7-1[/tex]
[tex]T_7 = 1 * \frac{2}{3}^{6[/tex]
[tex]T_7 = 1 * \frac{2^6}{3^6}[/tex]
[tex]T_7 = 1 * \frac{64}{729}[/tex]
[tex]T_7 = \frac{64}{729}[/tex]
