what is the length of leg s of the triangle below
Answer:
8
Step-by-step explanation:
[tex] \sin \: 45 \degree = \frac{s}{8 \sqrt{2} } \\ \\ \frac{1}{ \sqrt{2} } = \frac{s}{8 \sqrt{2} } \\ \\s = \frac{8 \sqrt{2} }{ \sqrt{2} } \\ \\ s = 8[/tex]