Answer: f(x)=(x-5)(x+5)(x+2)
Points given: (5,0),(-5,0),(-2,0)
To get the factors do x- the roots above:
Solve for x:
X+5=0 X=-5
X-5=0 X=5
X-2=0 X=2
Now we have (x-5),(x+5),(x+2)
Another point that seems to be given is (3,-80)
F(3)=-80= a(3-5)(3+5)(3+2)
-80=a(-2)(8)(5)
-80=a(-80) (Solve for a)
-80/-80=a(-80)/-80
1=a
F(x)=1(x-5)(x+5)(x+2)
