jjjanessaaa19 jjjanessaaa19
  • 15-04-2021
  • Mathematics
contestada

PLZ HELP!!! NEED HELP ASAP!!!!

PLZ HELP NEED HELP ASAP class=

Respuesta :

graciebean917
graciebean917 graciebean917
  • 15-04-2021

Answer:

(4/3, -3, 3/2)

Step-by-step explanation:

f(x)=6x^3+x^2-39x+36

0-6x^3-x^2+39x-36=0

-6x^3-18x^2+17x^2+51x-12x-36=0

-6x^2(x+3)+17(x+3)-12(x+3)=0

-(x=3)(6x^2-17x+12)=0

-(x+3)(6x^2-8x-9x+12)=0

-(x+3)(2x(3x-4)-3(3x-4))=0

-(x+3)(3x-4)(2-3)=0

(x=3)(3x-4)(2x-3)=0

x=-3 x=4/3 x=3/2

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