P varies inversely with the square of Q. When Q is 8, P 9. Find the value of P when Q is 3.
Answer:
P
[tex] \alpha [/tex]
1/q²
P=k/Q²
K=P×Q²
Where P=9
Q=8
K=?
K=9×8²
K=9×64
K=573
So where K= 573
Q=3
P=?
P=K/Q²
P=573/3²
P=573/9
P=63.67